Yang jago matematika minta tolong bgt dong caranya bsk dikumpulin semoga dapet pahala aminn

integral x / (x^2 - 2)^2/3 dx
= integral x (x^2-2)^-2/3 dx
misal u = x^2 -2
du/dx = 2x
dx = du/2x. maka
integral x (u)^-2/3 du/2x
= integral u^-2/3 du/2
= 1/2.u^(-2/3+1)/(-2/3+1)+ c
= 1/2.(u^1/3)/(1/3) + c
= 3/2(u^1/3) + c
= 3/2 (x^2-2)^1/3 + c. Jadi jawabannya B)