tentukan himpunan penyelesaian dari sistem persamaan linear 3x+4y=11 dan x+7y=15

3x + 4y = 11 (1)
x + 7y = 15 (2)
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Persamaan (2)

x + 7y = 15
x = 15 - 7y

Substitusi (1)

3x + 4y = 11
3(15 - 7y) + 4y = 11
45 - 21y + 4y = 11
-17y = 11 - 45
-17y = -34
y = -34/-17
y = 2

Substitusi (2)

x + 7y = 15
x + 7(2) = 15
x + 14 = 15
x = 15 - 14
x = 1

Jadi, Nilai

x = 1
y = 2

HP = {(x, y) = (1, 2)}

Semoga membantu :)