Bayangan kurva y= x2- 3x+ 1 di rotasikan sejauh 180° searah jarum jam dengan titik pusat 0 (0,0), kemudian dilanjutkan oleh pencerminan terhadap garis y= -x ada

jawab

T1 = R(180°)
T2 = Ry= - x
T2OT1(x,y)= (x',y')

[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}0&-1\\-1&0\end{array}\right] \left[\begin{array}{ccc}-1&0\\0&-1\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right]\, [/tex]

y = x'  dan x = y' substitusikan ke  y = x² -3x + 1
x'= y'² - 3y' + 1
atau
x = y² - 3y + 1