kak jawab yg ini dong cuman 1 soal aja

A(-2 , 2) ; B(2 , -1) ; C(5 , 3) ; D(1 , 6)

a. Gradien AB
m = Δy / Δx
m = (-1 - 2) / (2 + 2)
m = - ¾
Pers. : y - y₁ = m (x - x₁)
: y - 2 = -¾ (x + 2)
: y = -¾ x + ½

Gradien BC
m = (3 + 1) / (5 - 2)
m = [tex] \frac43 [/tex]

Pers : y - y₁ = m (x - x₁)
: y + 1 = [tex] \frac43 [/tex] (x - 2)
: y = [tex] \frac43x - \frac{11}3 [/tex]

Gradien CD
m = (6 - 3) / (1 - 5)
m = - ¾

Pers : y - y₁ = m(x - x₁)
: y - 3 = - ¾ (x - 5)
: y = - ¾ x + [tex] \frac{27}4 [/tex]

Gradien AD
m = (6 - 2) / (1 + 2)
m = [tex] \frac43 [/tex]

Pers : y - y₁ = m(x - x₁)
: y - 2 = [tex] \frac43 [/tex] (x + 2)
: y = [tex] \frac43x + \frac{14}3 [/tex]

b.
Lihat yang a.

Gradien AB = - ¾
Gradien BC = ⁴/₃
Gradien CD = - ¾
Gradien AD = ⁴/₃

c. AB sejajar DC
[tex] m_{AB} = m_{CD} [/tex]
- ¾ = - ¾ [qed]

BC sejajar AD
[tex] m_{BC} = m_{AD} [/tex]
⁴/₃ = ⁴/₃ [qed]

d. Gradien AC
m = (3 - 2) / (5 + 2)
m = ⅐

Persamaan : y - y₁ = m(x - x₁)
: y - 2 = ⅐(x + 2)
: y = ⅐ x + ¹⁶/₇

Gradien BD
m = (6 + 1) / (1 - 2)
m = -7

Persamaan : y - y₁ = m (x - x₁)
y + 1 = -7 (x - 2)
y = -7x + 13

e. m₁ x m₂ = -1
⅐ x (-7) = -1
-1 = -1 [qed]