tolong dibantu buatin isiin caranya ya

Persamaan Garis

15][
m1 = 1/3
Sejajar --> m2 = m1 = 1/3

PG dg gradien m = 1/3 dan melalui (x1,y1) = (5,-3) :
y - y1 = m(x - x1)
y + 3 = 1/3 (x - 5)
3y + 9 = x - 5
3y = x - 14 ✔

16][
m1 = -2/3
tegaklurus ---> m2 = -1/m1 = 3/2

PG dg m = 3/2 dan melalui (5,-3) :
y + 3 = 3/2 (x - 5)
2y + 6 = 3x - 15
2y = 3x - 21 ✔

17][
PG yg mlalui (-2,-4) dan (-4,3)
(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y + 4)/(3 + 4) = (x + 2)/(-4 + 2)
-2(y + 4) = 7(x + 2)
-2y - 7x = 8 + 14
-2y - 7x = 22 ✔

m1 = 1/3
syarat sejajar
m1 = m2 = 1/3
pers. garis yang melalui (5,-3) dan bergradien 1/3 adalah
y + 3 = 1/3 (x - 5)
y + 3 = x/3 - 5/3
y = x/3 - 5/3 - 9/3
y = x/3 - 14/3
3y = x - 14
3y - x = -14

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m1 = -2/3
syarat tegak lurus
m1 . m2 = -1
-2/3 , m2 = -1
m2 = 3/2

pers. garis yang melalui (5,-3) dan gradien 3/2 adalah
y + 3 = 3/2 (x - 5)
y = 3x/2 - 15/2 - 6/2
y = 3x/2 - 21/2
2y = 3x - 21
3x - 2y - 21 = 0

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(-2,-4) (-4,3)

(y + 4) / (3 + 4) = (x + 2) / (-4 + 2)
(y + 4) / 7 = (x + 2) / -2
-2(y + 4) = 7(x + 2)
-2y - 8 = 7x + 14
7x + 2y + 22 = 0