Matematika

Pertanyaan

tentukanhasil dari pembagian berikut!
a. (15a/6b2) : (20a2/24b3)
b. (2x2yz/3a) : (a2/xy2z) : (xyz2/6a4)

tolong dijawab plise

1 Jawaban

  • a) (15a / 6b² ) ÷ ( 20a² / 24b³ )
    = (15a ) (24b³)
    ---------------------
    ( 6b² ) ( 20a² )
    = (5a)(3) × (6b²)(4b)
    -----------------------------
    (5a)(4a) × (6b²)
    = 3 × 4b
    -------------
    4a
    = 12b
    ---------
    4a
    = (4)(3b)
    ------------
    (4)(a)
    = 3b
    --------
    a

    2) (2x²yz / 3a) ÷ (a² / xy²z) ÷ (xyz² / 6a⁴)
    = (2x²yz / 3a ) × (xy²z / a² ) × (6a⁴ / xyz²)
    = (2x²yz) × (xy²z) × (6a⁴)
    -----------------------------------
    ( 3a ) × ( a²) × (xyz²)
    = (2x³y³z²) × (6a⁴)
    ---------------------------
    (3a³) × (xyz²)
    = (xyz²)(2x²y²) × (3a³)(2a)
    -------------------------------------
    ( xyz²) × (3a³)
    = (2x²y²) × (2a)
    = 4ax²y²

Pertanyaan Lainnya