3log2=a dan 3 log5=b,maka 3 log150

³log2 = a
³log5 = b

³log150
= ³log(25 . 6)
= ³log25 + ³log6
= ³log5² + ³log(2 . 3)
= 2 .³log5 + ³log2 + ³log3
= 2b + a + 1

³log 2 = a
³log 5 = b

³log 150
= ³log(2 × 3 × 5²)
= ³log 2 + ³log 3 + ³log 5²
= a + 1 + 2b
= a + 2b + 1