tentukan persamaan garis lurus yg melalui titik (2,1) dan (3,6)!

Persamaan garis melalui (2,1),(3,6)
==> (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 1)/(6-1) = (x - 2)/(3-2)
(y -1)/5 = {x - 2)/1
1.(y - 1) = 5 (x -2)
y - 1 = 5x - 10
y = 5x -10+1
y = 5x -9
atau 5x - y -9 = 0