persamaan garis yang tegak lurus garis 2×-3y=4 dan melalui titik (1,3)

2x - 3y = 4
- 3y = - 2x + 4
m = - 2/-3
m = ⅔

tegak lurus => m1 . m2 = - 1
m1 . m2 = - 1
2/3 . m2 = - 1
m2 = - 1 ÷ 2/3
m2 = - 3/2

pers garis
y - y1 = m (x - x1)
y - 3 = - 3/2 (x - 1)
y = - 3/2 x + 3/2 + 3 (dikalikan 2)
2y = - 3x + 3 + 6
2y + 3x = 9