1. 122 F = C = K = R 2. 122 K = C = R = F 3. 72 R = C = F = K -tolong dijawab dngn benar , besok dikumpul.
Fisika
Dheadibaa
Pertanyaan
1. 122 F = C = K = R
2. 122 K = C = R = F
3. 72 R = C = F = K
-tolong dijawab dngn benar , besok dikumpul.
2. 122 K = C = R = F
3. 72 R = C = F = K
-tolong dijawab dngn benar , besok dikumpul.
1 Jawaban
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1. Jawaban yusakhalim1
1. 122°F = 226°C = -265,4K = 282,5°R
122°F = °C
122°F = 9/5 × t + 32°C
122°F = 9/5 × 122 + 32°C
122°F = 1.130/5°C
122°F = 226°C
122°F = K
122°F = 9/5 × (t-273) + 32K
122°F = 9/5 × (122-273) + 32K
122°F = 9/5 × (-151) + 32K
122°F = -1.327/5K
122°F = -265,4K
122°F = °R
122°F = 9/4 × t + 32°R
122°F = 9/4 × 122 + 32°R
122°F = 1.130/4°R
122°F = 282,5°R
2. 122K = 395°C = 220,75°R = 323°F
122K = °C
122K = (t + 273)°C
122K = (122+273)°C
122K = 395°C
122K = °R
122K = 5/4 × t + 273°R
122K = 5/4 × 122 + 273°R
122K = 883/4°R
122K = 220,75°R
122K = °F
122K = 5/9 × (t-32) + 273°F
122K = 5/9 × (122-32) + 273°F
122K = 5/9 × 90 + 273°F
122K = 5 × 10 + 273°F
122K = 50 + 273°F
122K = 323°F
3. 72°R = 57,6°C = 17,8°F = (-160,8)K
72°R = °C
72°R = 4/5 × t°C
72°R = 4/5 × 72°C
72°R = 288/5°C
72°R = 57,6°C
72°R = °F
72°R = 4/9 × (t-32)°F
72°R = 4/9 × (72-32)°F
72°R = 4/9 × 40°F
72°R = 160/9°F
72°R = 17,8°F
72°R = K
72°R = 4/5 × (t -273)K
72°R = 4/5 × (72-273)K
72°R = 4/5 × (-201)K
72°R = (-804/5K
72°R = (-160,8)K