Fisika

Pertanyaan

1. 122 F = C = K = R
2. 122 K = C = R = F
3. 72 R = C = F = K
-tolong dijawab dngn benar , besok dikumpul.

1 Jawaban

  • 1. 122°F = 226°C = -265,4K = 282,5°R


    122°F = °C

    122°F = 9/5 × t + 32°C

    122°F = 9/5 × 122 + 32°C

    122°F = 1.130/5°C

    122°F = 226°C

    122°F = K

    122°F = 9/5 × (t-273) + 32K

    122°F = 9/5 × (122-273) + 32K

    122°F = 9/5 × (-151) + 32K

    122°F = -1.327/5K

    122°F = -265,4K

    122°F = °R

    122°F = 9/4 × t + 32°R

    122°F = 9/4 × 122 + 32°R

    122°F = 1.130/4°R

    122°F = 282,5°R



    2. 122K = 395°C = 220,75°R = 323°F


    122K = °C

    122K = (t + 273)°C

    122K = (122+273)°C

    122K = 395°C

    122K = °R

    122K = 5/4 × t + 273°R

    122K = 5/4 × 122 + 273°R

    122K = 883/4°R

    122K = 220,75°R

    122K = °F

    122K = 5/9 × (t-32) + 273°F

    122K = 5/9 × (122-32) + 273°F

    122K = 5/9 × 90 + 273°F

    122K = 5 × 10 + 273°F

    122K = 50 + 273°F

    122K = 323°F


    3. 72°R = 57,6°C = 17,8°F = (-160,8)K


    72°R = °C

    72°R = 4/5 × t°C

    72°R = 4/5 × 72°C

    72°R = 288/5°C

    72°R = 57,6°C

    72°R = °F

    72°R = 4/9 × (t-32)°F

    72°R = 4/9 × (72-32)°F

    72°R = 4/9 × 40°F

    72°R = 160/9°F

    72°R = 17,8°F

    72°R = K

    72°R = 4/5 × (t -273)K

    72°R = 4/5 × (72-273)K

    72°R = 4/5 × (-201)K

    72°R = (-804/5K

    72°R = (-160,8)K

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