Persamaan sumbu simetri grafik fungsi kuadrat y=5x2-20x+1

Sumbu simetri = titik puncak

y = 5x^2-20x+1
a = 5
b = -20
c = 1

Xp = -b/2a = -(-20)/2(5) = 20/10 = 2
Yp = -(b^2-4ac)/4a = -((-20)^2-4(5)(1))/4(5) = (400-20)/20 = 380/20 = 19

Sumbu simetri = {2,19}