fanny tolong yah by. Rome

[tex]1. \\a. 4 + 5x < 3x + 9 \\ 2x < 5 \\ x < \frac{5}{2} \\ b. \\ c. \frac{x}{x - 4} = 12 \\ x = 12(x - 4) \\ x = 12x - 48 \\ - 11x = - 48 \\ x = \frac{48}{11} [/tex]
[tex]2. \\ a. {x}^{2} + \sqrt{x - 2} \\ {x}^{2} + x - 2 \geqslant 0 \\ (x - 1)(x + 2) \geqslant 0 \\ x = 1 \: v \: x = - 2 \\ b. \\ c. {x}^{2} \geqslant 5 \\ x \geqslant \sqrt{5} [/tex]
[tex]3. \\ fog = ({ {x}^{2} })^{2} + 2( {x}^{2} ) \\ fog = {x}^{4} + 2 {x}^{2} \\ gof = { ({x}^{2} + 2x)}^{2} \\ gof = {x}^{4} + 4 {x}^{3} + 4 {x}^{2} [/tex]
4. ??? ( belum pernah diajarin)
5.
[tex]5. \\ a. \frac{ {(x + 2)}^{2} - 4 }{2x - 4} \\ \frac{ {x}^{2} + 4x + 4 - 4}{2x - 4} \\ \frac{ {x}^{2} + 4x}{2x - 4} \\ diturunin \\ \frac{2x + 4}{2} \\ \frac{2(2) + 4}{2} \\ \frac{8}{2} = 4 \\ b.diturunkan \\ \frac{4 {x}^{3} + 6 {x}^{2} - 2x}{3} \\ \frac{4 {(1)}^{3} + 6 {(1)}^{2} - 2(1)}{3} \\ \frac{4 + 6 - 2}{3} \\ \frac{8}{3} [/tex]
Maaf kalo salah, semoga membantu
yg no 1 dan 2 udh agak lupa2 dan kurang bisa.
maaf kalo dpt nilai jelek