nomer 6 saja yang A.. bantu ya

A (1, 3) B (4, 6)
(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 3)/(6-3)= (x -1)/(4-1)
(y - 3)/3 = (x - 1)/3
y - 3 = x - 1
y = x -1 + 2
y = x +2
atau x - y +2 = 0