tentukan nilai a dan b pada fungsi f(×) =a×+b jika diketahui (a) f(2) =6 dan f (-5)-1 (b) f (-1)=-11 dan f (3)=1 #TlngDbntuYaTeman

f(x) = ax + b

f(2) = 6 maka f(2) = 2a + b = 6
f(-5) = -1 maka f(-5) = -5a + b = -1
f (-1) = -11 maka f(-1) = -a + b = -11
f(3) = 1 maka f(3) = 3a + b = 1

2a + b = 6
3a + b = 1
--------------- eliminasi (-)
-a = 5
a = -5

2a + b = 6
2(-5) + b = 6
-10 + b = 6
b = 16

kalo gak salah gitu