Matematika

Pertanyaan

Xavier, yaozhou and zara had some beads. xavier and yaozhao had a total of 438 beads. xavier and zara had a total of 204 beads. yaozhao had 3 times as many beads as zara. how many beads did xavier have ?

1 Jawaban

  • Xavier = X
    Yaozhou = Y
    Zara = Z

    x+y = 438
    x+z = 204 •••••(2)

    y = 3z

    x+y = 438
    x+3z = 438 ••••(1)

    x+3z = 438
    x+z = 204 (x3)
    -------------
    x+3z = 438
    3x+3z = 612
    -------------(dikurang)
    -2x = -174
    x = -174/-2
    x = 87 beads

    So, xavier has 87 beads

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