Fungsi f ditentukan oleh f(x) = ax + b. Jika pasangan pasangan berurutan (P, -3), (-3, q), (r, 2), (2, -2), dan (-2, 6) adalah anggota dari fungsi itu, nilai p,

f(x) = ax + b
y = ax + b

(2, -2)
-2 = 2a + b

(-2, 6)
6 = -2a + b

Eliminasi
2a + b = -2
-2a + b = 6
___________ -
4a = -8
a = -2

2a + b = -2
2(-2) + b = -2
-4 + b = -2
b = -2 + 4
b = 2

f(x) = -2x + 2

(p, -3)
-2p + 2 = -3
-2p = -3 - 2
-2p = -5
p = 5/2

(-3, q)
-2(-3) + 2 = q
6 + 2 = q
q = 8

(r, 2)
-2r + 2 = 2
-2r = 2 - 2
-2r = 0
r = 0

nilai p = 5/2, q = 8, r = 0