tentukan persamaan garis melalui titik (3,10) dan (-1,2)

(y-y1) / (y2-y1) = (x-x1) / (x2-x1)
(y-10) / (2-10) = (x-3) / (-1-3)
(y-10) / -8 = (x-3) / -4
-8(x-3) = -4(y-10)
-8x + 24 = -4y + 40
-8x + 4y + 24 - 40 = 0
-8x + 4y - 16 = 0