Tolonggggggg no 37 sama caranya thankss

sin3x = 3 sinx - 4 sin³x
cos3x = 4 cos³x - 3 cosx

sin6x
= 2 sin3x . cos3x
= 2(3 sinx - 4 sin³x) (4 cos³x - 3 cosx)
= 2 (12 sinx . cos³x - 9 sinx . cosx - 16 sin³x . cos³x + 12 sin³x . cosx)
= 2 sinx . cosx (12 cos²x - 9 - 16 sin²x . cos²x + 12 sin²x)
= sin2x (12(cos²x + sin²x) - 9 - 4 sin²2x)
= sin2x (12 - 9 - 4 sin²2x)
= sin2x (3 - 4 sin²2x)
= 3 sin2x - 4 sin³2x   ** E**