mohon dibantu please
Matematika
FahrezyHermawan
Pertanyaan
mohon dibantu please
2 Jawaban
-
1. Jawaban Iwan47
no. 9
PS/AB = PQ/AD
PS/33 = 16/24
ps = 33(2/3
PS = 22 -
2. Jawaban hardiansyahmuha
9. DA/PQ = AB/PS
24/16 = 33/PS
11/8 = 33/PS
PS = (33.8)/11
PS = 24
10. PQ/BC = QR/CD
12/18 = QR/24
QR = (12.24)/18
QR = 16
Tlng dikoreksi